Rod Stewart is rocking and rolling when it comes to his real estate holdings.
Just days after the British star’s former Malibu home listed for sale asking a princely $49.5 million, Stewart’s current Los Angeles compound has hit the market for $70 million.
The Wall Street Journal broke news of the listing.
European in its style, and standing in the gated North Beverly Park enclave, the property measures some 33,000 square feet with a pool and a soccer field. That latter fitting is no surprise; Stewart, 78, is a known soccer fan. So much so that, at one time, he was spotted in Malibu playing footie with the Scottish national team right on the beach after inviting them there to play.
Citing sales records, the Journal notes Stewart bought the property in 1991 for $12.08 million. He also owns a home in affluent Palm Beach, Florida.
Images show Old World-style touches such as ceiling moldings and medallions, herringbone floors, Corinthian columns, crystal chandeliers and marble floors decorated in a variety of patterns.
The main house has nine bedrooms, one of which is the primary suite with a sitting room and a terrace that looks over the pool. Images additionally show closets in the primary suite that are large enough to house Stewart’s massive shoe collection.
Elsewhere, there are entertaining areas, notably including a dazzling speakeasy with handsome jade green-painted walls. A main-floor great room also comes with a bar and, outside, there’s a loggia to spend time with guests al-fresco.
The listing also includes a guesthouse three stories tall and two gyms.
Michelle Oliver of Douglas Elliman has the listing and declined to tell the outlet why Stewart has decided to list. She added it’s fit for new owners who are looking for “a return to maximalism” and for “something that looks different and stands out.”
